Originally Posted by

**cyberdyne** Hi all,

My first post here so my apologies in advance if this is not the correct place to post this.

I have a right angled triangle with one angle of 25˚ (so clearly the last is 65˚). The hypotenuse is 17cm.

My question is how do I work out the other two sides please?

I'm guessing I have to use SIN and have found that:

SIN(A) = opposite(o)/hypotenuse(h)

SIN(65˚) = o/17

SIN(65˚) x 17 = o

0.8268 x 17 = o

o = 14.05

Am I on the right track?

Any help greatly appreciated.

Thank you in advance.