Trig / right angled triangles / SIN COS TAN
My first post here so my apologies in advance if this is not the correct place to post this.
I have a right angled triangle with one angle of 25˚ (so clearly the last is 65˚). The hypotenuse is 17cm.
My question is how do I work out the other two sides please?
I'm guessing I have to use SIN and have found that:
SIN(A) = opposite(o)/hypotenuse(h)
SIN(65˚) = o/17
SIN(65˚) x 17 = o
0.8268 x 17 = o
o = 14.05
Am I on the right track?
Any help greatly appreciated.
Thank you in advance.