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Math Help - Awkward Trig. Equation

  1. #1
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    Awkward Trig. Equation

    Hello all. I have a trig problem here that I am not necessarily stuck on, but just wanted to confirm results with someone else.

    Using the proof:

    \frac{\tan\alpha\pm\tan\beta}{1\mp\tan\alpha\tan\b  eta}

    Where:

    \tan\alpha = \frac{3\sqrt5}{5}
    \tan\beta = \frac{-\sqrt15}{4}

    For:

    \tan(\alpha+\beta)

    What do you get?
    Last edited by Deimos; May 5th 2010 at 11:11 PM.
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  2. #2
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    \frac{4(3\sqrt{5}+\sqrt{15})}{16-3\sqrt{75}}

    Can be simplified further.
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  3. #3
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    I made a mistake on \tan\alpha.

    I meant to write:

    \tan\alpha = \frac{3\sqrt5}{5}

    I fixed the initial post as well. Sorry about that.
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  4. #4
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    Hello Deimos

    With denominator rationalised, I get:
    \frac{(56\sqrt3-93)\sqrt5}{55}
    which checks out OK on my calculator.

    I don't think that will simplify any further.

    Grandad
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