use an algebraic method.
this is pretty simple but i can't figure it out.
i just need help working out the question.
the question is: 2sinθ-1=cscθ
the answers are 90°, 210°, 330°.
2sinθ-1= 1/sinθ
(2sinθ-1)*sinθ= (1/sinθ)*sinθ
2sin^2θ-sinθ= 1
sinθ(2sinθ-1)= 1
sinθ=1
θ=90°
2siθ°-1=1
2sinθ=2
sinθ=1
.... i can't get the answers 210° and 330°, which would make sinθ= -1/2
