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Math Help - height of a mountain with different elevations

  1. #1
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    height of a mountain with different elevations

    hello everybody,

    i got a height of a mountain problem but with a little twist. thanks for any help in advance.

    Determine the elevation (height above sea level) of the top of a mountain, Mount C. You take two measurements from the tops of two mountains with known elevations. All three mountain tops are in a line ( A then B then C), and all three mountain tops lie in the same plane. From the top of Mount A, with an elevation of 1240.8 feet above sea level, the angle of elevation to the top of Mount C is 16.8 degrees. From the top of Mount B, with and elevation of 1575.2 feet above sea level, the angle of elevation to the top of Mount C is 19.3 degrees. The distance along the ground from Mount A to Mount B is measured at 1742.6 feet. Find the elevation of Mount C above sea level.
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  2. #2
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    Quote Originally Posted by mikeyb View Post
    hello everybody,

    i got a height of a mountain problem but with a little twist. thanks for any help in advance.

    Determine the elevation (height above sea level) of the top of a mountain, Mount C. You take two measurements from the tops of two mountains with known elevations. All three mountain tops are in a line ( A then B then C), and all three mountain tops lie in the same plane. From the top of Mount A, with an elevation of 1240.8 feet above sea level, the angle of elevation to the top of Mount C is 16.8 degrees. From the top of Mount B, with and elevation of 1575.2 feet above sea level, the angle of elevation to the top of Mount C is 19.3 degrees. The distance along the ground from Mount A to Mount B is measured at 1742.6 feet. Find the elevation of Mount C above sea level.
    Let h be the height of the mountain C.
    Angle of elevation of C from B is 19.3 degrees. x is the distance between B and C. So
    tan(19.3) = (h-1575.2)/x.....(1)
    Angle of elevation of C from A is 16.8 degrees.So
    tan(16.8) = (h-1240.8)/(1742.6 + x)......(2)
    Substitute the value of x from equation 1 in eq.(2) and solve for h.
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  3. #3
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    Hello, mikeyb!

    I'll set it up for you . . .


    Determine the elevation (height above sea level) of the top of Mount C.
    You take two measurements from the tops of two mountains with known elevations.
    All three mountain tops are in a line (A, then B, then C),
    and all three mountain tops lie in the same plane.

    From the top of Mount A, with an elevation of 1240.8 feet above sea level,
    the angle of elevation to the top of Mount C is 16.8.

    From the top of Mount B, with and elevation of 1575.2 feet above sea level,
    the angle of elevation to the top of Mount C is 19.3.

    The distance along the ground from Mount A to Mount B is 1742.6 feet.

    Find the elevation of Mount C above sea level.
    Code:
                                          o C
                                      *   | 
                                  * *     |
                              *   *       | y
                          *     *         |
                      *       * 19.8     |
                  *       B o - - - - - - o S
              * 16.8       |             | 334.4
        A o - - - - - - - - + - - - - - - o T
          |                 |             |
          |                 |             |
    1240.8|                 |             | 1240.8
          |                 |             |
          |                 |             |
          * - - - - - - - - * - - - - - - *
          P     1742.6      Q      x      R

    Mount A is: . AP \:=\:1240.8 \:=\:TR, \quad \angle CAT = 16.8^o

    Mount B is: . BQ \,=\,1575.2 \quad\Rightarrow\quad ST \:=\:334.4,\quad \angle CBS = 19.8^o

    Mount C is: . CR \:=\:CS + ST + TR \;=\;y + 334.4 + 1240.8 .[1]

    PQ \:=\:1742.6 \quad\text{ Let }x \:=\:QR


    In right triangle CTA\!:\;\;\tan16.8^o \:=\:\frac{y+334.4}{x + 1742.6}

    . . . . . . y \;=\;x\tan16.8^o + 1742.6\tan16.8^o - 334.4 .[2]


    In right triangle CSB\!:\;\;\tan19.8^o \:=\:\frac{y}{x} \quad\Rightarrow\quad x \:=\:\frac{y}{\tan19.8^o} .[3]


    Substitute [3] into [2]: . y \;=\;\left(\frac{y}{\tan19.8^o}\right)\tan16.8^o + 1742.6\tan16.8^o - 334.4


    Solve for y . . . Substitute into [1].



    Edit: Too slow again . . . Sa-ri-ga-ma beat me to it . . . *sigh*
    .
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  4. #4
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    Thank you both guys I really appreciate your help!
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  5. #5
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    I dont know why but I cant solve this problem....

    y = (y/tan 19.3)tan 16.8 + 1742.6tan 16.8 - 334.4
    Brainfart to the extreme....
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  6. #6
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    Quote Originally Posted by mikeyb View Post
    I dont know why but I cant solve this problem....

    y = (y/tan 19.3)tan 16.8 + 1742.6tan 16.8 - 334.4
    Brainfart to the extreme....
    tan16.8/tan19.3 = 0.86
    y(1 - 0.86) = 0.14y. = 191.5
    So y = ....?
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