Hi. I've been trying to solve this trig. equation 4sin4t + 3cos4t = 0. The answer is meant to be t = $\displaystyle \frac{\pi}{4}-\frac{1}{4}\arctan(\frac{3}{4})$

$\displaystyle

4sin4t + 3cos4t = 0

$

$\displaystyle

4sin4t = - 3cos4t

$

$\displaystyle

tan4t = -\frac{3}{4}

$

$\displaystyle

4t = \arctan(\frac{3}{4})

$

$\displaystyle

t = \frac{1}{4}\arctan(\frac{3}{4})

$