# Right-Angled Triangles...

• May 3rd 2010, 04:44 AM
MathematicalThinker10
Right-Angled Triangles...
Hi,
I have posted here because I need some assistance with a trigonometry problem. I have found out that the answer is 11.2 to one decimal place but I can not work out how to do it.

The problem: http://i42.tinypic.com/1217mgg.jpg

Thank you.
• May 3rd 2010, 05:05 AM
sa-ri-ga-ma
Quote:

Originally Posted by MathematicalThinker10
Hi,
I have posted here because I need some assistance with a trigonometry problem. I have found out that the answer is 11.2 to one decimal place but I can not work out how to do it.

The problem: http://i42.tinypic.com/1217mgg.jpg

Thank you.

tan18 = BD/28
So BD = 28*tan(18)
tan36 = BC/28
So BC = 28tan(36)
x = BC - BD = ...?
• May 3rd 2010, 05:16 AM
MathematicalThinker10
Thank you.
I did not realize it was so simple...
• May 3rd 2010, 06:31 AM
mrmohamed
Quote:

Originally Posted by MathematicalThinker10
Hi,
I have posted here because I need some assistance with a trigonometry problem. I have found out that the answer is 11.2 to one decimal place but I can not work out how to do it.

The problem: http://i42.tinypic.com/1217mgg.jpg

Thank you.

HI all
aother solution
http://i69.servimg.com/u/f69/12/89/99/77/mathhe10.jpg
mrmohamed