Fundamental Identities

**nee** · May 2nd 2010, 02:04 PM

Factor:

cot^4x + 3cot^2x + 2

**masters** · May 2nd 2010, 03:07 PM

Originally Posted by nee

Factor:

cot^4x + 3cot^2x + 2

Hi nee,

$\cot^4 x+3 \cot^2x +2$ is in the form:

$x^4+3x^2+2$ , which can be factored into:

$(x^2+2)(x^2+1)$

Thus:

$\cot^4 x+3 \cot^2x +2=(\cot^2 x+2)(\cot^2 x+1)$

**nee** · May 2nd 2010, 03:25 PM

Thanks!

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