Can't quite tell exactly what you're doing.
Here's a way...
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find the exact value of sin(5pi/12)
here's what I have, can you tell me if I'm doing it correctly and if I've simplified. I'm more than a little confused.
[sin(5pi/6)]/2 = +/- √[(1-cosx)/2]
= +/- √{[1-cos(5pi/6)]/2}
= +/- √ ({1-[-√(3)/2]}/2)
= +/- √ {[1+√(3)/2]/2}
And that's as far as I got. I'm not sure if I'm doing it correctly or if i am, i have no idea how to simplify further. :/
Thanks ahead of time, all help is very much appreciated.