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Math Help - Trigonometric identities

  1. #1
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    Trigonometric identities

    Cos^4(theta)+Cos^2(theta)*sin^2(theta)+sin^2(theta  )=1
    ___

    This is being introduced at the end of a high-school Algebra II course, and is by far the most difficult, at least in my case, thing we've done all year.

    I've been having luck with some of the more basic of these proofs despite an arduous start, but as we progress further into this section, I'm getting pretty lost.

    Now, obviously there is factoring to be done here, but I really am unsure of where to start.

    Any help would be greatly appreciated.
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  2. #2
    Super Member Deadstar's Avatar
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    Quote Originally Posted by Caturdayz View Post
    Cos^4(theta)+Cos^2(theta)*sin^2(theta)+sin^2(theta  )=1
    ___

    This is being introduced at the end of a high-school Algebra II course, and is by far the most difficult, at least in my case, thing we've done all year.

    I've been having luck with some of the more basic of these proofs despite an arduous start, but as we progress further into this section, I'm getting pretty lost.

    Now, obviously there is factoring to be done here, but I really am unsure of where to start.

    Any help would be greatly appreciated.
    I'll do a small part of it. Hopefully you'll see how to finish...

    \cos^4(\theta) + \cos^2(\theta) \sin^2(\theta) = \cos^2(\theta)(\cos^2(\theta) + \sin^2(\theta)) = \cos^2(\theta)

    Since \cos^2(\theta) + \sin^2(\theta) = 1
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  3. #3
    Junior Member mrmohamed's Avatar
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    [quote=Caturdayz;503961] Cos^4(theta)+Cos^2(theta)*sin^2(theta)+sin^2(theta  )=1

    HI all
    another way
    cos^4 a = (1- sin^2a)^2
    =(1- sin^2a)^2 + sin^2a(1-sin^2a)+sin^2a
    =1 - 2 sin^2a +sin^4a+sin^2a - sin^4a + sin^2a
    = 1- 2 sin^2a+2sin^2a - sin^4a + sin^4a = 1
    mrmohamed
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