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Math Help - Simplification, Half Angles?

  1. #1
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    Simplification, Half Angles?

    I am COMPLETELY lost with this problem.. Ive tried to get help from a number of people and no one seems to be able to help. Here is the problem, if it could be worked out and explained i would greatly appreciate it. Can't even find similar problems in my book.

    Square root of 1-cos(12B)/2
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  2. #2
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    Quote Originally Posted by Taylormade View Post
    I am COMPLETELY lost with this problem.. Ive tried to get help from a number of people and no one seems to be able to help. Here is the problem, if it could be worked out and explained i would greatly appreciate it. Can't even find similar problems in my book.

    Square root of 1-cos(12B)/2
    Is it
     \sqrt{1-\frac{\cos (12B)}{2}}

    or more likely,
     \sqrt{\frac{1-\cos (12B)}{2}} ?
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  3. #3
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    Quote Originally Posted by Gusbob View Post
    Is it
     \sqrt{1-\frac{\cos (12B)}{2}}

    or more likely,
     \sqrt{\frac{1-\cos (12B)}{2}} ?

    The 2nd one, sorry I dont know how to input math problems like that hah.
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  4. #4
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    Quote Originally Posted by Taylormade View Post
    The 2nd one, sorry I dont know how to input math problems like that hah.
    Sorry I had to leave.

     \sqrt{\frac{1-\cos(12B)}{2}} =  \sqrt{\frac{1-\cos(2(6B))}{2}}

    Now  \cos 2\theta = 1 - 2\sin ^2 \theta . Apply this to cos 12B with  6B = \theta
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