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Math Help - Sinusoids

  1. #1
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    Sinusoids

    How do you graph f(x)=13*sin(pi/2X-pi/4)+4? specifically
    I understand what each number does in terms of 13= vert stretch, pi/2 is horizontal compression/stretch, pi/4 is horizontal shift right, and +4 is vertical shift up....

    But how do you graph it via translating it from the points of a regular sin graph? In terms of radians.
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  2. #2
    Master Of Puppets
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    Your function can be written as

    f(x)=13\sin\left(\frac{\pi}{2}x-\frac{\pi}{4}\right)+4 \implies f(x)=13\sin \frac{\pi}{2}\left(x-\frac{1}{2}\right)+4

    The general fucntion is \sin x = 1\sin 1(x-0)+0

    Can you see how this now looks like yours?
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