# Sinusoids

• April 26th 2010, 02:16 PM
bluepuppy922
Sinusoids
How do you graph f(x)=13*sin(pi/2X-pi/4)+4? specifically
I understand what each number does in terms of 13= vert stretch, pi/2 is horizontal compression/stretch, pi/4 is horizontal shift right, and +4 is vertical shift up....

But how do you graph it via translating it from the points of a regular sin graph? In terms of radians.
• April 26th 2010, 02:24 PM
pickslides
Your function can be written as

$f(x)=13\sin\left(\frac{\pi}{2}x-\frac{\pi}{4}\right)+4 \implies f(x)=13\sin \frac{\pi}{2}\left(x-\frac{1}{2}\right)+4$

The general fucntion is $\sin x = 1\sin 1(x-0)+0$

Can you see how this now looks like yours?