
Sinusoids
How do you graph f(x)=13*sin(pi/2Xpi/4)+4? specifically
I understand what each number does in terms of 13= vert stretch, pi/2 is horizontal compression/stretch, pi/4 is horizontal shift right, and +4 is vertical shift up....
But how do you graph it via translating it from the points of a regular sin graph? In terms of radians.

Your function can be written as
$\displaystyle f(x)=13\sin\left(\frac{\pi}{2}x\frac{\pi}{4}\right)+4 \implies f(x)=13\sin \frac{\pi}{2}\left(x\frac{1}{2}\right)+4$
The general fucntion is $\displaystyle \sin x = 1\sin 1(x0)+0$
Can you see how this now looks like yours?