Hey, the question is:
Show that the equation tan x = 4cos x may be written as
4sin^2x + sin x -4= o
Anyone know how to do this? Thanks!
Hello, LoveDeathCab!
. . . . - . . .sin xShow that the equation: .tan x .= .4·cos x
may be written as: .4·sin²x + sin x - 4 .= .0
We have: .------ .= .4·cos x
. . . . - . . .cos x
Multiply by cos x: .sin x .= .4·cos²x
Then we have: .sin x .= .4(1 - sin²x) . → . sin x .= .4 - 4·sin²x
Therefore: . 4·sin²x + sin x - 4 .= .0