1. ## Tricky sin equation

Hello!
This is the equation Im stuck with:
$2sin (0.5x) = 3/3x+2$

Im not sure where to start, because I cant take out any of the x values,

should i let 0.5x be a completely new vale like 'y' and but then i will still be stuck

Thank you!

2. Originally Posted by appleseed
Hello!
This is the equation Im stuck with:
$2sin (0.5x) = 3/3x+2$

Im not sure where to start, because I cant take out any of the x values,

should i let 0.5x be a completely new vale like 'y' and but then i will still be stuck

Thank you!
What is required in the problem? Do you want to find the value of x? If yes, how much decimal places in x is required ?
In the form of infinite series sinθ can be written as
sinθ = θ - (θ)^3/3! + (θ)^5/5! and so on.

3. Originally Posted by sa-ri-ga-ma
What is required in the problem? Do you want to find the value of x? If yes, how much decimal places in x is required ?
In the form of infinite series sinθ can be written as
sinθ = θ - (θ)^3/3! + (θ)^5/5! and so on.

Hello!

Thank you so much for the reply!!!

Yes i am asked to find the value of x and the answer is required to 3 s.f.

It might be better if i give you the context of the equation.

''''''''''''There are two equations g(x) and f(x), There are two values of x for which the gradient of f is equal to the gradient
of g. Find both these values of x. '''''''''"

So i've already found the derivative of the two equations and i've checked that its correct, and then i equated the two derivatives, but i dont know how to find x.

I was thinking that maybe it could be done by trig identities, lol but i dont know how though

anyways Thank you! !!

4. Hello appleseed

There are infinitely many solutions to the equation
$2\sin(\tfrac12x)=\frac{3}{3x+2}$
which is what I assume you meant. (You should have written 3/(3x+2) if you don't know how to write it using LaTeX.)

Have a look at the diagram I've attached, where I've plotted the graph of each side separately.

You won't be able to solve an equation like this to get exact answers. You'll have to use a numerical method - e.g. Newton-Raphson. Do you know how?

Hello appleseed

There are infinitely many solutions to the equation
$2\sin(\tfrac12x)=\frac{3}{3x+2}$
which is what I assume you meant. (You should have written 3/(3x+2) if you don't know how to write it using LaTeX.)

Have a look at the diagram I've attached, where I've plotted the graph of each side separately.

You won't be able to solve an equation like this to get exact answers. You'll have to use a numerical method - e.g. Newton-Raphson. Do you know how?

I think i've heard of Newton-Raphson before, but i cant remember exactly how to find the answer using it. Could you briefly go over the steps please?

Thanks!

6. ## Newton-Raphson method

Hello appleseed
Originally Posted by appleseed

I think i've heard of Newton-Raphson before, but i cant remember exactly how to find the answer using it. Could you briefly go over the steps please?

Thanks!
If you've not had any practice with this method, this is not the easiest example to start with.

If you want to get a solution to the equation
$f(x) = 0$
and you have a first approximation, $x = a_1$, to the answer, then a second approximation, $a_2$, is given by
$a_2=a_1-\frac{f(a_1)}{f'(a_1)}$
In this case you'll have to let
$f(x) = 2\sin(\tfrac12x)-\frac{3}{3x+2}$
So
$f'(x) = \cos(\tfrac12x) +\frac{9}{(3x+2)^2}$
From the graph, there's a solution close to $x = 1$. So with $a_1 = 1$ we get
$a_2 = 1-\frac{f(1)}{f'(1)}$
$\approx 0.7$
... and so on.

The next approximation, $a_3$, uses $0.7$ as the starting value:
$a_3 = 0.7 -\frac{f(0.7)}{f'(0.7)}$
$\approx 0.73$ (to 2 d.p.)
Repeating the process, to 4 d.p., I make the answer $0.7314$.

The next positive solution is around $x = 6$. To 4 d.p., the solution converges very quickly to $6.1361$.