Bearing issues!
Can someone please explain what bearing is exactly? I'm not totally sure how to solve problems regarding it, as I don't understand it completely.
Heres an example:
A sailing boat sets off from a point X and heads towards Y, a point 17 km north. At point Y, it changes direction and heads towards point Z, a point 12 km away on a bearing of 90 degrees. Once at Z, the crew wants to sail back to X. Calculate:
a.) The distance ZX
b.) the bearing of X from Z
Hello nsingh201To find the bearing of B from A:Originally Posted by nsingh201
Can someone please explain what bearing is exactly? I'm not totally sure how to solve problems regarding it, as I don't understand it completely.
Heres an example:
A sailing boat sets off from a point X and heads towards Y, a point 17 km north. At point Y, it changes direction and heads towards point Z, a point 12 km away on a bearing of 90 degrees. Once at Z, the crew wants to sail back to X. Calculate:
a.) The distance ZX
b.) the bearing of X from Z
Imagine you're standing at A.In this question
Face due North.
Turn clockwise until you're facing B.
The angle you've turned through is the bearing of B from A.
We want the bearing of X from Z. So, you're standing at Z, facing North. Turn clockwise until you're facing X. You've turned through
So that's the bearing of X from Z:(to the nearest degree).
Grandad
Hi nsingh201,Can someone please explain what bearing is exactly? I'm not totally sure how to solve problems regarding it, as I don't understand it completely.
Heres an example:
A sailing boat sets off from a point X and heads towards Y, a point 17 km north. At point Y, it changes direction and heads towards point Z, a point 12 km away on a bearing of 90 degrees. Once at Z, the crew wants to sail back to X. Calculate:
a.) The distance ZX
b.) the bearing of X from Z
You can use the Pythagorean theorem to find the distance ZX since you turned 90 degrees East. See diagram.
Grandad found your required bearing to head home.
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