Hello nsingh201 Quote:

Originally Posted by

**nsingh201** Can someone please explain what bearing is exactly? I'm not totally sure how to solve problems regarding it, as I don't understand it completely.

__Heres an example:__

A sailing boat sets off from a point X and heads towards Y, a point 17 km north. At point Y, it changes direction and heads towards point Z, a point 12 km away on a bearing of 90 degrees. Once at Z, the crew wants to sail back to X. Calculate:

a.) The distance ZX

b.) the bearing of X from Z

(Thinking)

To find the bearing of B from A:Imagine you're standing at A.

Face due North.

Turn clockwise until you're facing B.

The angle you've turned through is the bearing of B from A.

In this question$\displaystyle \tan \angle YZX = \frac{17}{12}$

$\displaystyle \Rightarrow \angle YZX = 54.8^o$

We want the bearing of X from Z. So, you're standing at Z, facing North. Turn clockwise until you're facing X. You've turned through$\displaystyle 270^o - 54.8^o$$\displaystyle =215.2^o$

So that's the bearing of X from Z: $\displaystyle 215^o$ (to the nearest degree).

Grandad