Quote:

A ferris wheel with a diameter of 24 m rotates at a rate of 3 minutes/revolution.

Riders board the Ferris wheel 2 m above the ground.

A couple boards the Ferris wheel and the ride states.

(a) How far above the ground is the couple 30 seconds after the ride starts?

(b) How many *seconds* will it be (after the ride starts) before the couple

is 17 m above the ground for the __second__ time?

So first, for (a) I went about developing the equation and i got:

. . h .= .12·cos(pi/90(t-90)) + 14 .I don't follow this

so plug in 30 for t and get 8 meters above the ground, correct? .but this is correct!

and then i need some help with (b).