1 - tanx sinx = cos2x + sin²x I think i finally created a proper iidentity.. I just need somebody to try and prove it! Thanks
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Originally Posted by advancedfunctions2010 1 - tanx sinx = cos2x + sin²x RHS cos2x = cos²x - sin²x Therefore, the RHS = cos²x LHS 1 - tanx sinx = cos²x + sin²x - tanx sinx LHS =! RHS unless sin²x = tanx sinx
Im not sure what you mean?
Originally Posted by advancedfunctions2010 1 - tanx sinx = cos2x + sin²x I think i finally created a proper iidentity.. I just need somebody to try and prove it! Thanks So the identity you have created cannot be equal. however, if you change your LHS to : In this case, your RHS will be equal to LHS giving you a proper identity.
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