Please Bare with Me.. Can you prove this identity?

1 - tanx sinx = cos2x + sin²x




I think i finally created a proper iidentity.. I just need somebody to try and prove it!


Thanks

Quote:

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Originally Posted by advancedfunctions2010

1 - tanx sinx = cos2x + sin²x

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RHS
cos2x = cos²x - sin²x

Therefore, the RHS = cos²x

LHS
1 - tanx sinx = cos²x + sin²x - tanx sinx

LHS =! RHS unless sin²x = tanx sinx

Im not sure what you mean?

Quote:

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Originally Posted by advancedfunctions2010

1 - tanx sinx = cos2x + sin²x




I think i finally created a proper iidentity.. I just need somebody to try and prove it!


Thanks

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So the identity you have created cannot be equal.

however, if you change your LHS to :







In this case, your RHS will be equal to LHS giving you a proper identity.