Let f(x) = sin2x and g(x) = sin(0.5x). And f(x) = g(x)
Then
sin(2x) = sin(0.5x)
sin(2x) - sin(x/2) = 0....(1)
Using
sinC - sinD = 2cos[(C+D)/2]sin[(C-D)/2]
simplify eq(1) and solve foe x.
Let f(x) = sin2x and g(x) = sin(0.5x).
Consider the equation f(x) = g(x).
Find the number of solutions to this equation, for 0 less than or equal to x less than or equal to 3pi/2.
I know there are four solutions from graphing by hand and that I can determine the solutions using a graphing calculator. BUT how do I determine the solutions by hand?