Solve the equation exactly for 0 ≤ t ≤ 2pi. tan(2θ) - tanθ = 0.
I know tan 2θ = (2tanθ)/(1-tan^2) and tanθ = sinθ/cosθ
But that is where I get stumped. What would I need to do next? turn the 2(tan θ) on the left to 2(sinθ/cosθ)? Also the tanθ to sinθ/cosθ?
I hope you can help me with this problem and explain to me the process as well. Thank you so much.
Yes I can thank you so much for helping me on this. I was going crazy trying to convert that thing into sin or cos so I could solve it. I never thought about leaving it just in tangent form and then solving it from there. Excellent work on showing your work, it was really helpful.