I have this problem:

lim (x-->1) sin(2x)/3xI multiplied the whole thing by 2/2 and took a 2/3 out of the limit, so I then have:

2/3 [lim(x-->1) sin(2x)/2xWhich of course is very similar to the sinx/x limit, but the variable is approaching 1, not 0 in this case...

Would it be correct to do this:

Let z = x-1and turn the equation into:

x-->1, then z-->0

(2/3) [lim(z-->0) sin2(z+1)/2(z+1)I feel like this isn't going to get me anywhere useful...

Any tips, please? I appreciate it.