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Math Help - Dividing/Multiplying fractions+square roots...

  1. #1
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    Arrow Dividing/Multiplying fractions+square roots...

    Is this correct?

    sq. root of 2 / 2 = 40 / sq. root of 3/2
    = 80 / sq. root of 6

    ( refer to attachment for better understanding )

    I don't know if that is proper multiplication/division?



    Thanks.
    Attached Thumbnails Attached Thumbnails Dividing/Multiplying fractions+square roots...-division.jpg  
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  2. #2
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    Quote Originally Posted by advancedfunctions2010 View Post
    Is this correct?

    sq. root of 2 / 2 = 40 / sq. root of 3/2
    = 80 / sq. root of 6

    ( refer to attachment for better understanding )

    I don't know if that is proper multiplication/division?


    Thanks.
     \frac{\sqrt 2}{2} \neq \frac{40}{\sqrt {\frac{3}{2}}} Not even close. How did you get this?

    But  \frac{40}{\sqrt{\frac{3}{2}}} = \frac{80}{\sqrt 6}
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  3. #3
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    Im not sure.

    This all relates to my previous post, regarding the 2 right angle triangles..


    How did you get this?
    <br />
\frac{40}{\sqrt{\frac{3}{2}}} = \frac{80}{\sqrt 6}<br />
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  4. #4
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by advancedfunctions2010 View Post
    Im not sure.

    This all relates to my previous post, regarding the 2 right angle triangles..


    How did you get this?
    <br />
\frac{40}{\sqrt{\frac{3}{2}}} = \frac{80}{\sqrt 6}<br />
    \frac{40}{\sqrt{\frac{3}{2}}} = \frac{40 \times 2}{\frac{\sqrt 3}{\sqrt 2}\times 2}= \frac{40 \times 2}{\frac{\sqrt 3}{\sqrt 2}\times (\sqrt 2 \times \sqrt 2)}= \frac{80}{{\sqrt 3}\times{\sqrt 2}}=\frac{80}{\sqrt 6}
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  5. #5
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    thank you so much
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