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Thread: Trig Ratios & Special Angles

  1. April 14th 2010, 01:38 PM #1
    advancedfunctions2010
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    Wink Trig Ratios & Special Angles

    I don't know how to even start.
    Please help, w/ steps!

    An irregular building lot in a subdivison has the shape shown:
    ( in attachment )


    a) Determine an exact expression for the length side of X

    b) Determine an approximation for X, to the nearest tenth of a metre.


    Please Help!
    Attached Thumbnails Attached Thumbnails Trig Ratios & Special Angles-pi-question.jpg  
    Last edited by advancedfunctions2010; April 14th 2010 at 02:04 PM.
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  2. April 14th 2010, 02:17 PM #2
    pickslides
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    To find the length x you must first find the length of the line between the 2 triangles. Call it y and solve for it.

    Here's a kick start

    \sin \frac{\pi}{3} = \frac{40}{y}\implies y = \frac{40}{\sin \frac{\pi}{3}}

    After you have y use it here

    \cos \frac{\pi}{4} = \frac{x}{y}
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