am trying to find the value for x between 0 and 360 degress. but i think am doing something wrong.

$\displaystyle 2-sinx = cos^2x + 7sin^2x$

$\displaystyle 2-sinx = 1-sin^2x + 7sin^2x$

$\displaystyle 2-sinx = 1- 6sin^2x$

can someone help me to solve this am stuck here..