Hi,

Can someone help me with this problem?

Find the angle of depression from the top of a light-house 250 feet above water level to the water line of a ship 2 miles offshore.

Thank you so much,

Isabel

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- Apr 18th 2007, 08:06 PMcuteisa89Angle of depression
Hi,

Can someone help me with this problem?

Find the angle of depression from the top of a light-house 250 feet above water level to the water line of a ship 2 miles offshore.

Thank you so much,

Isabel - Apr 18th 2007, 08:20 PMecMathGeek
I hope you know how to use the trig functions.

This is a right triangle, where the length of the opposite side is 250ft, the adjacent side is 2miles, and we're looking for the measure of the acute angle.

First, we need to have the units be the same:

A = 250 ft

B = 2 miles = 2*5280 ft = 10560 ft

tan(x) = A/B = 250/10560

x = arctan(250/10560) = 0.023669821 radians = 1.35618085 degrees

I hope this answers your question - Apr 18th 2007, 08:21 PMJhevon
- Apr 18th 2007, 08:25 PMecMathGeek
- Apr 18th 2007, 08:39 PMJhevon