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Math Help - trig basics

  1. #1
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    trig basics

    if csc theta = a/b
    what are the other five trigonometric angles for theta?
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  2. #2
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by way123 View Post
    if csc theta = a/b
    what are the other five trigonometric angles for theta?
    If you have a right angled triangle, with adjacent(perpendicular) = p, hypotenuse = h, and base = b, then with respect to angle \theta, the trigonometric functions are defined as:

    sin\theta = \frac{p}{h}

    likewise,

    csc\theta = \frac{1}{sin\theta}=\frac{h}{p}

    you have \frac{h}{p} = \frac{a}{b}

    use Pythagorean Theorem to find the base (b), and calculate the remaining trigonometric functions.

    This link might be helpful:

    Trigonometric functions - Wikipedia, the free encyclopedia
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  3. #3
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    right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
    so would it be like
    sec theta = root(b squared - a squared) all over b
    ?
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  4. #4
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by way123 View Post
    right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
    so would it be like
    sec theta = root(b squared - a squared) all over b
    ?
    Your question has:

    csc\theta = \frac{a}{b}

    that is:

    \frac{\text{hypotenuse}}{\text{adjacent}} = \frac{a}{b}

    By pythagoras theorem:

    {\text{hypotenuse}^2} =  {\text{adjacent}^2}+{\text{base}^2}

    so,

    a^2 = b^2 + x^2 where x is the base

    now find he value of x from this equation. Then you will have the values of hypotenuse, adjacent, and base. Then find the trigonometric functions from the link that I provided in the above post!
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  5. #5
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by way123 View Post
    right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
    so would it be like
    sec theta = root(b squared - a squared) all over b
    ?
    It would be like this,but your value for sec\theta is incorrect
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