1. ## trig basics

if csc theta = a/b
what are the other five trigonometric angles for theta?

2. Originally Posted by way123
if csc theta = a/b
what are the other five trigonometric angles for theta?
If you have a right angled triangle, with adjacent(perpendicular) = p, hypotenuse = h, and base = b, then with respect to angle $\theta$, the trigonometric functions are defined as:

$sin\theta = \frac{p}{h}$

likewise,

$csc\theta = \frac{1}{sin\theta}=\frac{h}{p}$

you have $\frac{h}{p} = \frac{a}{b}$

use Pythagorean Theorem to find the base (b), and calculate the remaining trigonometric functions.

Trigonometric functions - Wikipedia, the free encyclopedia

3. right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
so would it be like
sec theta = root(b squared - a squared) all over b
?

4. Originally Posted by way123
right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
so would it be like
sec theta = root(b squared - a squared) all over b
?

$csc\theta = \frac{a}{b}$

that is:

$\frac{\text{hypotenuse}}{\text{adjacent}} = \frac{a}{b}$

By pythagoras theorem:

${\text{hypotenuse}^2} = {\text{adjacent}^2}+{\text{base}^2}$

so,

$a^2 = b^2 + x^2$ where x is the base

now find he value of x from this equation. Then you will have the values of hypotenuse, adjacent, and base. Then find the trigonometric functions from the link that I provided in the above post!

5. Originally Posted by way123
right i got that one but i wasnt given the third side. so i would i have to put it in terms of the other side lengths?
so would it be like
sec theta = root(b squared - a squared) all over b
?
It would be like this,but your value for $sec\theta$ is incorrect