It's ok. I have managed to solve this now. It was much easier than I had been thinking!
Stuck on this question:
By using the sum and different formulas for cos(phi+theta) and cos(phi-theta) with phi=1/2(A+B) and theta=1/2(A-B),
(i) derive the formula
cos A+cos B=2 cos(1/2(A+B))cos(1/2(A-B))
(ii) and then must I derive the formula
cos A-cos B= -2 sin(1/2(A+B))sin(1/2(A-B)) from part (i) above.