Trig Proof

**sigma1** · April 9th 2010, 02:28 PM

i have been trying to crack this but i have had no luck. hope someone can help.

$(sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

**Deadstar** · April 9th 2010, 03:19 PM

Originally Posted by sigma1

i have been trying to crack this but i have had no luck. hope someone can help.

$(sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

What exactly are you trying to crack?

$\sin(n \pi) = 0$ for $n = \pm 1$ , $\pm 2$ , ...

$\tan(n \pi) = 0$ for $n = \pm 1$ , $\pm 2$ , ...

Hence both sides = 0.

**Deadstar** · April 9th 2010, 03:23 PM

Oh yeah and the Latex for pi (not pie lol) is...

\pi $\pi$

**sigma1** · April 9th 2010, 05:32 PM

the actual question is prove that

$<br /> (sin4A + sin2A)/(cos4A+cos2A) = tan3A<br />$

Math Help - Trig Proof

LinkBack

Thread Tools

Display

Trig Proof

Similar Math Help Forum Discussions

trig proof help

trig proof

Trig proof - urg

Help with a Trig Proof

Trig Proof

Search Tags