Trig Proof

**sigma1** · Apr 9th 2010, 01:28 PM

i have been trying to crack this but i have had no luck. hope someone can help.

$(sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

**Deadstar** · Apr 9th 2010, 02:19 PM

Originally Posted by sigma1

i have been trying to crack this but i have had no luck. hope someone can help.

$(sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

What exactly are you trying to crack?

$\sin(n \pi) = 0$ for $n = \pm 1$ , $\pm 2$ , ...

$\tan(n \pi) = 0$ for $n = \pm 1$ , $\pm 2$ , ...

Hence both sides = 0.

**Deadstar** · Apr 9th 2010, 02:23 PM

Oh yeah and the Latex for pi (not pie lol) is...

\pi $\pi$

**sigma1** · Apr 9th 2010, 04:32 PM

the actual question is prove that

$<br /> (sin4A + sin2A)/(cos4A+cos2A) = tan3A<br />$

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