Thread: Trig Proof

i have been trying to crack this but i have had no luck. hope someone can help.

$\displaystyle (sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

Originally Posted by sigma1

i have been trying to crack this but i have had no luck. hope someone can help.

$\displaystyle (sin4x + sin2x)/(cos4x+cos2x) = tan3x$

the X varibale is actually (pie), i just could not type it into the window...

What exactly are you trying to crack?

$\displaystyle \sin(n \pi) = 0$ for $\displaystyle n = \pm 1$,$\displaystyle \pm 2$, ...

$\displaystyle \tan(n \pi) = 0$ for $\displaystyle n = \pm 1$,$\displaystyle \pm 2$, ...

Hence both sides = 0.

Oh yeah and the Latex for pi (not pie lol) is...

\pi $\displaystyle \pi$

the actual question is prove that

$\displaystyle
(sin4A + sin2A)/(cos4A+cos2A) = tan3A
$