Solve the equation with 0 ≤ α ≤ 2pi. Give exact answers if possible.
sin(2α) + 3 = 4
I need help isolating the sin so that it is by itself. How would I do that? I get stuck at this point:
sin(2α) + 3 = 4
sin(2α) = 1
What would I need to do next in order to isolate sin in order to solve this problem? Thank you.
Sorry if I'm misundertanding, but do you mean you really want to "isolate sin" as in end up with sin = something? Just in case you were thinking of that, I think you are a bit confused about what sin means. "sin" is just a trigonometric function that can't stand on its own.
Having is like having
To solve for whatever is inside the sin function (e.g. sin(x)), you take the arcsin of both sides [just like you would square both sides to solve for what's in the square root].
Hope that clears things up
Mathemagister
PS If you already knew everything I just said and I misinterpreted your words, no harm no foul!