simple trig equation
ok so i have been doing these trig equations for a while now...and i came up with this suspicious easy one..can anybody tell me if what im doing is right?
cos^2x = 1
took the square root of both sides and ended up with cos x = 1... then i took the inverse of cos (1) and came up with 0.. now im checking when cos is positive, and it turns out its in Q 1 and 4
so in Q1 its the same as the related acute which is 0 and in Q 4 its 2 pi - 0 which gives 2 pi...
is this right? is it ok to take the square root of both sides to remove the squared in the cosine??
You missed some stuff...
Originally Posted by magmagod
if , .
Your answers of and were correct, however, it will also be equal to at , , etc...
So when , .
But we also have solutions when , this happens at , , , etc...
I.e. when , .
Here's a graph of . Not.e where the graph is equal to 1. i.e. at the top of the 'waves'.