Hello banku12 Originally Posted by
banku12 Let angleA B C be angles of a triagnle ABC
if $\displaystyle cos^2\frac{B}{2}+cos^2\frac{C}{2}+cosA=3/2$
and $\displaystyle sinC + sinB = xsinA$
then find the value of $\displaystyle x$
Are you sure you have this question correct?
I assume that $\displaystyle x$ is supposed to have a constant value, but my spreadsheet calculations show that this is not so. For example:
$\displaystyle B = 40^o$ gives $\displaystyle C = 32.16462...^o, A = 107.83538^o$ and $\displaystyle x = 1.234469$
whereas
$\displaystyle B = 60^o$ gives $\displaystyle C = 16.7785^o, A = 103.2214^o$ and $\displaystyle x = 1.18614$
Check the question again, please.
Grandad