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Math Help - Need Urgent Trig Help!

  1. #1
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    Need Urgent Trig Help!

    Here is the question.

    Q: Jasper walks 2km due west (270). He then turns and walks 3km southeast (135)

    a) How far is Jasper from his starting point? Round your answer to the nearest 2 decimal places.

    b) What is the direction of Jasper's destination in relation to his starting point? Round your
    answer to the nearest degree.
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by MathDumb View Post
    Here is the question.

    Q: Jasper walks 2km due west (270). He then turns and walks 3km southeast (135)

    a) How far is Jasper from his starting point? Round your answer to the nearest 2 decimal places.

    b) What is the direction of Jasper's destination in relation to his starting point? Round your
    answer to the nearest degree.
    Hi MathDumb,

    I'll set up the first part for you.

    Walking 2 miles due West and then turning 135 degrees southeast will make a 45 degree angle with the due West line.

    This is the included angle between distances 2 and 3.

    The third side of the triangle represents the distance he is from his original starting point.

    Use law of cosines to determine this value.

    c^2=a^2+b^2-2ab \cos C

    c^2=2^2+3^2-2(3)(2)\cos 45
    Attached Thumbnails Attached Thumbnails Need Urgent Trig Help!-1.jpg  
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  3. #3
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    Thank you so much. I worked out the problem and got an answer of 4.51 Km. Thank you so much again!
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  4. #4
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    For part B I got 28 degrees before subtracting anything. Like so:

    SinC/c = SinA/a

    Sin45/4.51 = SinA/3

    3Sin45/4.51 = SinA

    = 28 Degrees. Do I go any further from here?
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