# Math Help - Which identity to change when solving an equation like this

1. ## Which identity to change when solving an equation like this

Hi
Where would you start?

I am trying to get to one trig function and used a few different identities but am going round in circles!
I though to express them all as cosine...then sine and I have just ended up going back on myself

2. Hi

$\frac{2}{\cos(2x)}-\frac{\cos(2x)}{\sin(2x)} = \frac{\sin(2x)}{\cos(2x)}$

$\frac{2\:\sin(2x)-\cos^2(2x)-\sin^2(2x)}{\cos(2x)\:\sin(2x)} = 0$

$\frac{2\:\sin(2x)-1}{\cos(2x)\:\sin(2x)} = 0$

3. Thanks
So that would leave me to solve arscin .05 and then divide all answers by two in the given range?

4. Yes
It leads to $x=\frac{\pi}{12} [\pi]$ or $x=\frac{5\pi}{12} [\pi]$

5. Brilliant
Thanks!