# Thread: need help with ln problem

1. ## need help with ln problem

ln [x/ (1-x)] = 1.5014
What is x?

How do I go about solving this problem?

The only thing I've come up with so far is
ln p -ln(1-p)=1.5014
but that doesn't really help me.

thanks

2. Remember that $e^{\ln(x)} = x$... where $e$ is the exponential function.

Taking exponentials of both sides gives you...

$\frac{x}{1-x} = e^{1.5014}$

Can you finish?

3. thank you for your help

i got 0.8179