Results 1 to 8 of 8

- March 25th 2010, 03:04 PM #1

- Joined
- Jan 2009
- From
- Ontario Canada
- Posts
- 243

## Need help with this example.

An observer in a helicopter 250 m above ground notes that the angle of the depression of the top of the tree is 18 degrees. Tree height is 12 m. How far from directly below the helicopter is the tree??

How do I figure this out with trig ratios.

Explain, so I can see what is done.

Thanks

Joanne

I can't figure out how the picture of this would look like. is the helicopter above the tree??? and if so, how do you figure out the height?? I am lost on this one. thanks

- March 25th 2010, 05:19 PM #2

- Joined
- Jun 2009
- Posts
- 806
- Thanks
- 4

- March 25th 2010, 05:46 PM #3

- Joined
- Jan 2009
- From
- Ontario Canada
- Posts
- 243

- March 25th 2010, 06:10 PM #4

- Joined
- Jan 2009
- From
- Ontario Canada
- Posts
- 243

The question says, depression of the top of the tree of 18 degrees.

So that means the angle is facing down from the horizontal line from the top of the tree right????

Is the depression of the top of the tree is what is confusing me.

If the plane in just above the tree, how does the angle play in this, if its asking how far is the plane from the tree. 238m??????

So the plane is right above the tree?? That is where I am lost.

- March 25th 2010, 06:28 PM #5

- March 25th 2010, 06:40 PM #6

- Joined
- Jan 2009
- From
- Ontario Canada
- Posts
- 243

- March 25th 2010, 07:51 PM #7

- Joined
- Jun 2009
- Posts
- 806
- Thanks
- 4

- March 26th 2010, 01:18 AM #8