show that: a) (1 - sin^2[a])(1 + tan^2[a]) = 1 b) (1 - cos^2[a])/(sec^2[a] - 1) = 1 - sin^2[a] i would be greatfull to recieve step by step answers
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Originally Posted by T_o_M show that: a) (1 - sin^2[a])(1 + tan^2[a]) = 1 Use pythagoren identities, 1-sin^2a=cos^2a And 1+tan^2a=sec^2a=1/cos^2a When you multiply them out you get, (cos^2a)(1/cos^2a)=1
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