show that:

a) (1 - sin^2[a])(1 + tan^2[a]) = 1

b) (1 - cos^2[a])/(sec^2[a] - 1) = 1 - sin^2[a]

i would be greatfull to recieve step by step answers :)

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- Apr 11th 2007, 04:34 AMT_o_Midentity
show that:

a) (1 - sin^2[a])(1 + tan^2[a]) = 1

b) (1 - cos^2[a])/(sec^2[a] - 1) = 1 - sin^2[a]

i would be greatfull to recieve step by step answers :) - Apr 11th 2007, 04:52 AMThePerfectHacker