Hi
Can anyone tell me how to do this:
If cosecant A=3.168 find secant A
-I understand that secant=1/cos and that cosecant is 1/sin but I am still confused
Thanks a lot to anyone who took the time to read this!
ok, so you know the relationships, so use them. here's how
i will use csc for cosecant and sec for secant
cscA = 3.168
=> 1/sinA = 3.168
=> sinA = 1/3.168 = 0.316
now we know that sin^2(A) + cos^2(A) = 1
we know the value of sinA so let's plug it in to find cosA
=> (0.316)^2 + cos^2(A) = 1
=> cos^2A = 1 - (0.316)^2 = 0.9
=> cosA = 0.949
so cosA = 0.949
=> 1/cosA = 1/0.949 = 1.054
=> secA = 1.054....
i rounded off some stuff while doing this problem, if you want a more accurate answer you can redo this with more decimal places
Hello, stephie!
. . . . . . . . . . . . . . . - . . . . . . . . . . __If csc A = 3.168, find sec A.
That decimal looks suspiciously like √10.
. . . . . . . . . . . . . . . . __
. . . . . . . . . . . . . . . √10 . - . hyp
We have: . csc A .= .------ .= .-----
. . . . . . . . . . . . . . . . 1 . - . . opp
. . . . . . . . . . . . . . . . . . . . . . . . - . . . - . . . . . . . . __
Hence, A is an angle in a right triangle with: .hyp = √10 and opp = 1.
Using Pythagorus, we find that: .adj = 3
. . . . . . . . . . . . . . . . . . . . . . .__
. . . . . . . . . . . . . . . .hyp . . . √10
Therefore: . sec A .= .----- .= .-----
. . . . . . . . . . . . . - . .adj . . . . .3