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F(t)=-sin2t + 2cos2t=0 What is the value of t for this equation ?

Quote: Originally Posted by nyasha F(t)=-sin2t + 2cos2t=0 What is the value of t for this equation ? 2cos(2t) = sin(2t) Or tan(2t) = 2. Do you want to find the value of t in degrees? In that case 2t = arctan(2). Then find t.