Find the value of
. . . . is in Quadrant 2
The final answer should be: . . I'm not getting this
We have: .
Then:. . . .
And we have: .
What's going on?
Hello everyone, I came across an old trigonometry problem which I'm not able to solve again and it's driving me crazy, here it is:
find the value of tan(x+y) knowing that:
sin(y)=cos(y/3) with 19pi/4<=y<=5pi ( y in [19pi/4;5pi] ).
The final answer should be tan (x+y)= sqrt(2)-3.
My only problem is that I've a really hard time to find y. I tried to add pi/2 on both side to have cos or sin on both sides but it didn't help then I tried with a variable, pi/3=a => sin(3a)=cos(a) => sin(a)(4cosˆ2(a)-1)=cos(a) but then again it led me to nothing...
Can you please explain to me how to find y.
( I did the problem backwards and you should fin tan(y)=1-sqrt(2)).
Thanks in advance!!
RJH, I've a last question for you. How did you proceed to find that:
because I looked how you started and I wanted to try to do the rest by myself but I got stuck at that step...
Do you have a methode or something, I know that you want to find something with the same power and I was looking for this, but by just "randomly" trying to find what it could be it would have taken me a while...
So any advice if I come across something like this again?