(sinθ-cosθ)^2 = sin^2 θ-2sinθcosθ-cos^2 θ is this all?? what else can i do?
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Originally Posted by somanyquestions (sinθ-cosθ)^2 = sin^2 θ-2sinθcosθ+cos^2 θ is this all?? what else can i do? two identities involved here ... (1) the basic Pythagorean identity ... (2) the double angle identity for sine ... ...
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