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Math Help - Trig Functions

  1. #1
    Newbie
    Joined
    Mar 2010
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    12

    Trig Functions

    Hi all,

    can someone please check to see if i have this questions correct from a worksheet.
    simplify the expression:

    (cosec x ) / (tanx + cot x)

    = (1/sin x)/[(sin x/cosx) + {(1/sinx) / (sin x / cos x)}]

    = (1/sinx)/(1/cosx)


    if that makes sense.

    how do you guys actually make fractions on here?

    thanks,
    Mitch
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  2. #2
    Super Member

    Joined
    May 2006
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    Lexington, MA (USA)
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    Hello, Mitch281008!

    Simplify: . \frac{\csc x}{\tan x + \cot x}

    = \;\frac{\;\dfrac{1}{\sin x}\;}{\dfrac{\sin x}{\cos x}}+ \frac{\;\dfrac{1}{\sin x}\;}{\dfrac{\sin x}{\cos x}} . . . . no!
    Does \frac{1}{2+3} \;=\;\frac{1}{2} + \frac{1}{3} ?


    You have: . \frac{\dfrac{1}{\sin x}} {\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}}


    \text{Multiply by }\frac{\sin x\cos x}{\sin x\cos x}\!:\;\;\frac{\sin x\cos x\left(\dfrac{1}{\sin x}\right)} {\sin x\cos x\left(\dfrac{\sin x}{\cos x} + \dfrac{\cos x}{\sin x}\right)} . =\; \frac{\cos x}{\sin^2\!x + \cos^2\!x} \;=\;\frac{\cos x}{1} \;=\;\cos x

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