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Originally Posted by purplec16 note that this is not an easy equation to solve by hand.
(sure that you posted it correctly?)
If correct, then I recommend you graph the left side of the equation over the interval from to and locate the zeros using your calculator.
Originally Posted by purplec16 The sine of the half-angle formula should (?) help here:
Hello purplec16 Originally Posted by purplec16 If you're going to try for an analytical solution, you can reduce this equation to a quartic in , where , using . The equation then becomes: but, apart from adopting a numerical/graphical method (as skeeter suggested), I can't see what to do next.
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