Your line will beAn equation of the tangent line to the curve
at the point is y =
(point intercept form: y = mx+b)
I know it's easier to fine f(3π) ans f'(3π) and then simplifty the exact value of sin(3π) and cos(3π)...
So I got
f(3π) = 3π((5cos(3π)-9sin(3π))) = -15π
f'(3π) = 3π(-5sin(3π)-9cos(3π))+5cos(3π)-9sin(3π) = -26.99
but I dont know what to do with these values and or if i've gone to correct way of solving this. any help would be wonderful!