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Thread: trigonometric Functions (again...)

  1. #1
    Junior Member
    Mar 2007

    Post trigonometric Functions (again...)

    I'm trying to solve these two problems.

    1. Use the given function values and trigonometric indentites to find the indicated trigonometric functions.

    sec = 5, tan = 2*sqrt(6)
    a) cos θ. I have found that it is 1/5 though I'm not sure.
    b) cot θ. I have sqrt(6)/12
    c) cot(90 - θ). I don't know how to solve this one
    d) sin θ. This one neither.

    2. Find the values of θ in degrees and radians.
    a) cot θ = sqrt(3)/3
    b) sec θ = sqrt(2). I have for this one 45 degrees and pi/4

    I'll be really REALLY grateful if somebody can help. Anyways you guys always do so thanks a million!!

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  2. #2
    Apr 2007
    First of all, I assume that when you say
    sec = 5, tan = 2*sqrt(6)
    that you are actually saying : sec(θ)=5 and tan(θ)=2

    a) Correct. cos(θ)=1/sec(θ)=1/5
    b) Correct. cot(θ)=1/tan(θ)=1/(26)=6/12
    Assume that 90 is in degrees.
    c) cot(90-θ)=tan(θ)= 26
    d) tan(θ)=sin(θ)/cos(θ)
    sin(θ)=( 26)(1/sec(θ))
    sin(θ)= ( 26)(1/5)
    sin(θ)= (26)/5

    a) cot(θ)= (√3/3) multiply that by (√3/√3) you get
    cot(θ) is u/v, you take it from there? Does your teacher want all possible values of θ or just one?
    b) is correct if you are looking for just one value of θ.

    hope that helped.
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  3. #3
    Junior Member
    Mar 2007


    Thanks for helping. For the second question, my teacher only wanted one value so I'm pretty much done. Thanks for helping ....really appreciate it!

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