# trigonometric Functions (again...)

• Apr 4th 2007, 07:28 PM
cuteisa89
trigonometric Functions (again...)
Hi,
I'm trying to solve these two problems.

1. Use the given function values and trigonometric indentites to find the indicated trigonometric functions.

sec = 5, tan = 2*sqrt(6)
a) cos θ. I have found that it is 1/5 though I'm not sure.
b) cot θ. I have sqrt(6)/12
c) cot(90 - θ). I don't know how to solve this one
d) sin θ. This one neither.

2. Find the values of θ in degrees and radians.
a) cot θ = sqrt(3)/3
b) sec θ = sqrt(2). I have for this one 45 degrees and pi/4

I'll be really REALLY grateful if somebody can help. Anyways you guys always do so thanks a million!! :)

Isabel
• Apr 6th 2007, 05:22 PM
First of all, I assume that when you say
Quote:

sec = 5, tan = 2*sqrt(6)
that you are actually saying : sec(θ)=5 and tan(θ)=2
6.

a) Correct. cos(θ)=1/sec(θ)=1/5
b) Correct. cot(θ)=1/tan(θ)=1/(26)=6/12
Assume that 90 is in degrees.
c) cot(90-θ)=tan(θ)= 26
d) tan(θ)=sin(θ)/cos(θ)
sin(θ)=tan(θ)cos(θ)
sin(θ)=( 26)(1/sec(θ))
sin(θ)= ( 26)(1/5)
sin(θ)= (26)/5

a) cot(θ)= (√3/3) multiply that by (√3/√3) you get
1/√3
cot(θ) is u/v, you take it from there? Does your teacher want all possible values of θ or just one?
b) is correct if you are looking for just one value of θ.

hope that helped.
• Apr 6th 2007, 07:26 PM
cuteisa89
Thanks
Thanks for helping. For the second question, my teacher only wanted one value so I'm pretty much done. Thanks for helping ....really appreciate it! :)

Isabel