Prove (Secθ-tanθ)/(Secθ+tanθ) = 1- 2 Secθ X tanθ + 2 tanēθ
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Hello prantik007 Originally Posted by prantik007 Prove (Secθ-tanθ)/(Secθ+tanθ) = 1- 2 Secθ X tanθ + 2 tanēθ Using the identities: and multiplying top-and-bottom by , we get: Grandad
Thanks
Last edited by prantik007; March 9th 2010 at 09:01 AM.
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