$\displaystyle \frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta} $ Kindly solve it covering all the steps ...
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Originally Posted by Sanjana Das $\displaystyle \frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta} $ Kindly solve it covering all the steps ... A better idea is to show us what you have done and where you are stuck. Hint: Convert everything into a function of sines and cosines using $\displaystyle \tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$ and $\displaystyle \sec{\theta} = \frac{1}{\cos{\theta}}$.
When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter ..
Originally Posted by Sanjana Das When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter .. I really hate having to repeat myself, but actually show us what you have done and where you are stuck...
Yes. it is.
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