1. ## Prove that..

$

\frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta}

$

Kindly solve it covering all the steps ...

2. Originally Posted by Sanjana Das
$

\frac{tan \theta +sec \theta -1}{tan \theta - sec \theta +1}= \frac{1 + sin \theta}{cos \theta}

$

Kindly solve it covering all the steps ...
A better idea is to show us what you have done and where you are stuck.

Hint: Convert everything into a function of sines and cosines using

$\tan{\theta} = \frac{\sin{\theta}}{\cos{\theta}}$

and

$\sec{\theta} = \frac{1}{\cos{\theta}}$.

3. When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter ..

4. Originally Posted by Sanjana Das
When I solved my LHS was not coming equal to RHS n it was coming very long do u have any trick or something which can make it shorter ..
I really hate having to repeat myself, but actually show us what you have done and where you are stuck...

5. Yes. it is.